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Rs aggarwal solutions

A horse is placed for grazing inside a rectangular field 70 m by 52 m. It is tethered to one corner by a rope 21 m long. On how much area can it graze? How much area is left ungrazed?

Length of rectangular field = L = 70 m

Breadth of rectangular field = B = 52 m

So, Area of the field = L x B

= 70×52 = 3640

Area of the field is 3640 m^2

And, Area of the quadrant of radius 21 m = 1/4 x 22/7 x 21 x 21

= 346.5 m^2

Area available for grazing = (Area of the field) - (Area of the quadrant of radius 21 m)

= 3640 - 346.5

= 3293.5 m^2

**Thus, 3293.5 m^2 area is left ungrazed.**

Length of rectangular field = L = 70 m

Breadth of rectangular field = B = 52 m

So, Area of the field = L x B

= 70×52 = 3640

Area of the field is 3640 m^2

And, Area of the quadrant of radius 21 m = 1/4 x 22/7 x 21 x 21

= 346.5 m^2

Area available for grazing = (Area of the field) - (Area of the quadrant of radius 21 m)

= 3640 - 346.5

= 3293.5 m^2

**Thus, 3293.5 m^2 area is left ungrazed.**

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